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91 234 Retrotransposons
wea25324_ch23_732-758.indd Page 745 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile 23.4 Retrotransposons 16 (a) 34 condition known as severe combined immunodeficiency (SCID, “bubble boy” syndrome) and cannot mount an immune response against any pathogen. They must be isolated from the rest of the world in order to survive. (d) RAG1 – – + RAG2 – – + + (c) (b) Signal 12 23 – RAG1+2 – + – + – + 61 50 HP HP HP 745 SUMMARY RAG1 and RAG2 introduce singlestrand nicks into DNA adjacent to either a 12 signal or a 23 signal. This leads to a transesterification in which the newly created 39-hydroxyl group attacks the opposite strand, breaking it, and forming a hairpin at the end of the coding segment. The hairpins then break in an imprecise way, allowing joining of coding regions with loss of bases or gain of extra bases. 23.4 Retrotransposons 16 M1 2345 6 N M1 2 N M1 2 3 4 Figure 23.17 Identifying cleavage products. (a) Cleavage substrate. Gellert and colleagues constructed this labeled 50-mer, which included 16 bp of DNA on the left, then a 12 signal (yellow), included in a 34-bp segment on the right. The single 59-end label is indicated by the red dot. These workers also made an analogous 61-mer substrate with a 23 signal. (b) Identifying the hairpin product. Gellert and coworkers incubated RAG1 and RAG2 proteins, as indicated at top, with either the labeled 12-signal or 23-signal substrate, also as indicated at top. After the incubation, they subjected the products to nondenaturing gel electrophoresis and autoradiographed the gel to detect the labeled products. The positions of the 61-mer and 50-mer substrates, the hairpin (HP), and the 16-mer are indicated at right. (c) Identifying the products from a nondenaturing gel. Gellert and colleagues recovered the labeled products (apparently uncleaved 50-mer substrate and 16-mer fragment) from the bands of a nondenaturing gel. They then electrophoresed these DNAs again in lanes 1 and 2, respectively, of a denaturing gel, along with markers (identified with diagrams at right) corresponding to the uncleaved substrate, the 16-bp hairpin (HP), and the single-stranded 16-mer released by denaturing the nicked substrate. (d) Requirement for RAG1 and RAG2. This experiment was very similar to the one in panel (b) except that the presence of RAG1 and RAG2 proteins (indicated at top) were the only variables. “N” denotes the position of the 16-mer released from the nicked species. (Source: McBlane, J.F., D.C. Van Gent, D.A. Ramsden, C. Romeo, C.A. Cuomo, M. Gellert, and M.A. Oettinger, Cleavage at a V(D)J recombination signal requires only RAG1 and RAG2 proteins and occurs in two steps. Cell 83 (3 Nov 1995) f. 4 a–c, p. 390. Reprinted by permission of Elsevier Science.) closely resembles rearrangement of immunoglobulin genes. Without antibodies, B cells are useless, and without T cell receptors, T cells are useless. Thus, loss of Artemis function means loss of both B cell and T cell function. Indeed, people with defective Artemis genes have a very serious McClintock’s maize transposons are examples of so-called cut-and-paste or copy-and-paste transposons, similar to the bacterial transposons we discussed earlier in this chapter. If DNA replication is involved, it is direct replication. Humans also carry transposons in this class, which constitute about 1.6% of the human genome. The most prevalent example is called mariner, but all of the mariner elements studied so far have been defective in transposition. Eukaryotes also carry many more transposons of another kind: retrotransposons, which replicate through an RNA intermediate. In this respect, the retrotransposons resemble retroviruses, some of which cause tumors in vertebrates, and some of which (the human immunodeficiency viruses, or HIVs) cause AIDS. As an introduction to the replication scheme of the retrotransposons, let us first examine the replication of the retroviruses. Retroviruses The most salient feature of a retrovirus, indeed the feature that gives this class of viruses its name, is its ability to make a DNA copy of its RNA genome. This reaction, RNA→DNA, is the reverse of the transcription reaction, so it is commonly called reverse transcription. In 1970, Howard Temin and, simultaneously, David Baltimore convinced a skeptical scientific community that this reaction takes place. They did so by finding that the virus particles contain an enzyme that catalyzes the reverse transcription reaction. Inevitably, this enzyme has been dubbed reverse transcriptase. A more proper name is RNA-dependent DNA polymerase. Figure 23.18 illustrates the retrovirus replication cycle. We start with a virus infecting a cell. The virus contains two copies of its RNA genome, linked together by base pairing at their 59-ends (for simplicity, only one copy is wea25324_ch23_732-758.indd Page 746 746 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile Chapter 23 / Transposition RNA: Reverse transcription LTR LTR dsDNA: Integration Host DNA Host DNA Provirus: Transcription RNA: Packaging into virus; budding Figure 23.18 Retrovirus replication cycle. The viral genome is an RNA, with long terminal repeats (LTRs, green) at each end. Reverse transcriptase makes a linear, double-stranded DNA copy of the RNA, which then integrates into the host DNA (black), creating the provirus form. The host RNA polymerase II transcribes the provirus, forming genomic RNA. The viral RNA is packaged into a virus particle, which buds out of the cell and infects another cell, starting the cycle over again. shown). When the virus enters a cell, its reverse transcriptase (a product of the viral pol gene) makes a doublestranded DNA copy of the viral RNA, with long terminal repeats (LTRs) at each end. This DNA recombines with the host genome to yield an integrated form of the viral genome called the provirus. The host RNA polymerase II transcribes the provirus, yielding viral mRNAs, which are then translated to viral proteins. To complete the replication cycle, polymerase II also makes RNA copies of the provirus, which are new viral genomes. These genomic RNAs are packaged into virus particles (Figure 23.19) that bud out of the infected cell and go on to infect other cells. Evidence for Reverse Transcriptase The skepticism about the reverse transcription reaction arose from the fact that no one had ever observed it, and the notion that it violated the “central dogma of molecular biology” promulgated by Watson and Crick, which said that the flow of genetic information is from DNA to RNA to protein, not the reverse. Crick later stated that the DNA→RNA arrow was intended to be double-headed, but that was clearly not the popular perception at the time. What evidence did Baltimore and Temin bring to bear to dispel this skepticism? Figure 23.20 shows the result of one of Baltimore’s experiments. He incubated purified retrovirus particles (Raucher mouse leukemia virus, or R-MLV) with all four dNTPs, including [3H]dTTP, then measured the incorporation of the labeled TTP into a polymer (DNA) that could be precipitated with acid. He observed a clear incorporation (red curve) that could be inhibited by including RNase in the reaction (blue curve), and inhibited even more by preincubating with RNase (green curve). This sensitivity to RNase was compatible with the hypothesis that RNA is the template in the reverse transcription reaction. Baltimore also examined the product of the reaction and showed that it was insensitive to RNase and base hydrolysis, but sensitive to DNase. Furthermore, the virions could support the incorporation of dNTPs only. Ribonucleotides, including ATP, could not be incorporated. Thus, the product behaved like DNA, and the enzyme behaved like an RNA-dependent DNA polymerase—a reverse transcriptase. Baltimore and Temin both performed similar experiments on Rous sarcoma virus particles, with very similar results. Thus, it appeared that all RNA tumor viruses probably contained reverse transcriptase and behaved according to the provirus hypothesis illustrated in Figure 23.18. This has proven to be true. Evidence for a tRNA Primer As molecular biologists began to investigate the molecular biology of reverse transcription, they discovered that the viral reverse transcriptase is like every other DNA polymerase known: It requires a primer. In 1971, Baltimore and colleagues found RNA primers attached to the 59-ends of nascent reverse transcripts using the following strategy: They labeled the nascent reverse transcripts in avian myeloblastosis virus (AMV) by the same method Baltimore and Temin had used—incubating virus particles with labeled dNTPs. Then they subjected the products to Cs2SO4 gradient ultracentrifugation to separate RNA from DNA based on their densities (RNA being denser than DNA). In the first experiment, Baltimore and colleagues isolated the nucleic acids from the virus particles and subjected them immediately to ultracentrifugation. Figure 23.21a shows the results: a peak of labeled DNA that appeared to have the density of RNA. This finding is consistent with the hypothesis that the nascent DNA is still base-paired to the much bigger RNA template, so the whole complex behaves like RNA. If this hypothesis is true, then heating the RNA–DNA hybrid should denature it and release the DNA product as an independent molecule. When Baltimore and colleagues performed that experiment, they observed the behavior in Figure 23.21b: Now the nascent DNA product had a density much closer to that of DNA, but still a little too dense, as if there were still some RNA attached. That behavior could be explained if the nascent DNA still had an RNA primer covalently attached to it. To check this possibility, Baltimore and coworkers treated the nascent DNA with RNase and again subjected it to ultracentrifugation. This time, the density of the product behaved exactly as expected for pure DNA (Figure 23.21c). Thus, the nascent reverse transcript appears to be primed by RNA. But what RNA? wea25324_ch23_732-758.indd Page 747 23/12/10 10:42 AM user-f467 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile 23.4 Retrotransposons 747 Figure 23.19 AIDS virion internal structure, cutaway artwork. AIDS (acquired immune deficiency syndrome) is caused by the human immunodeficiency virus (HIV). The core of this HIV virus particle is a capsule (pink) containing RNA strands (ribonucleic acid, yellow). Around the core is an icosahedral shell of matrix proteins (blue). Over this is a membrane envelope (yellow bilayer) taken from the membrane of the host cell that made this virus particle. Anchored to the shell are viral knobs (yellow) that allow the virus particle to attach to cells. AIDS impairs the immune system and allows often fatal secondary infections. In the process of making an inventory of all the molecules within the retrovirus particle, molecular biologists had discovered some tRNAs, one of which, host tRNATrp, appeared to be partially base-paired to the viral RNA. Could this be the primer? If so, it should bind to the reverse transcriptase. To see if it does, Baltimore, James Dahlberg, and colleagues labeled host tRNATrp, or the tRNATrp from virus particles, with 32P and mixed these labeled tRNAs with AMV reverse transcriptase. Then they subjected these mixtures to gel filtration on Sephadex G-100 (Chapter 5). By itself, tRNATrp was included in the gel and eluted in a peak centered at about fraction #25. However, both host and virion tRNAs, when mixed with reverse transcriptase eluted with the enzyme in a peak centered at about fraction #20. Thus, this reverse transcriptase binds tRNATrp. Together with the data we have already discussed, the binding data strongly suggest that tRNATrp serves as the primer for this enzyme. The virus does not encode a tRNA, so the primer must be picked up from the host cell. (Source: © Russell Kightley/Photo Researchers, Inc.) The Mechanism of Retrovirus Replication The initial product of reverse transcription in vitro is a short piece of DNA called strong-stop DNA. The reason for the strongstop is obvious when we consider the site on the viral RNA to which the tRNA primer hybridizes (the primer-binding site, or PBS). It is only about 150 nt (depending on the retrovirus) from the 59-end of the viral RNA. This means that the reverse transcriptase will synthesize DNA for just 150 nt or so before reaching the end of the RNA template and stopping. This raises the interesting question: What happens next? That question is related to another paradox of retrovirus replication, illustrated in Figure 23.22. The provirus is longer than the viral RNA, yet the viral RNA serves as the template for making the provirus. In particular, the LTRs wea25324_ch23_732-758.indd Page 748 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile Chapter 23 / Transposition RNA [3H]TMP incorporated (cpm in hundreds) 25 No treatment 20 (a) H 2O (b) 15 (c) 10 RNase in reaction 1 3 1 3 1 1.65 5 Preincubation with RNase 30 60 90 Time (min) 120 Figure 23.20 Effect of RNase on reverse transcriptase activity. Baltimore incubated R-MLV particles with the four dNTPs, including [3H]dTTP, under various conditions, then acid-precipitated the product and measured the radioactivity of the product by liquid scintillation counting. Treatments: red, no extra treatment; purple, preincubation for 20 min with water; blue, RNase included in the reaction; green, preincubated with RNase. (Source: Adapted from Baltimore, D., Viral RNAdependent DNA polymerase. Nature 226:1210, 1970.) in the viral RNA are incomplete. The left LTR contains a redundant region (R) plus a 59-untranslated region (U5), whereas the right LTR contains an R region plus a 39-untranslated region (U3). How can the provirus have complete LTRs on each end while its template is missing a U3 region at its left end and a U5 region at its right end? Harold Varmus proposed an answer based on the important fact that reverse transcriptase has another distinct activity: an RNase activity. The RNase inherent in reverse transcriptase is RNase H, which specifically degrades the RNA part of an RNA–DNA hybrid. Varmus’s hypothesis is illustrated in Figure 23.23. First, (a) the reverse transcriptase uses the tRNA to prime synthesis of strong-stop DNA. This appears at first to be the end of the line, but then (b) RNase H recognizes a stretch of RNA hybrid between the strong-stop DNA and the RNA template, and degrades the R and U5 parts of the RNA. The removal of this RNA leaves a tail of DNA (blue) that can hybridize through its R region with the RNA at the other end of the RNA template, or with another RNA template (c). This hybridization to another R region is called the “first jump.” In principle, the DNA could jump to the other end of the same RNA, and this could be facilitated by looping the RNA around so the strong-stop DNA does not even need to leave the left end of the RNA to pair with the right end. But the DNA can also jump to another viral RNA, and this seems likely DNA 3 [3H]DNA (cpm in hundreds) 748 12/21/10 1.44 1.42 Density (g/mL) Figure 23.21 Reverse transcripts contain an RNA primer. Baltimore and colleagues labeled reverse transcripts in AMV particles with [3H]dTTP, then subjected them to Cs2SO4 gradient ultracentrifugation after the following treatments: (a) no treatment; (b) heating to denature double-stranded polynucleotides; and (c) heating and RNase to remove any primers attached to the reverse transcripts. Interpretive drawings at right provide an explanation for the results: (a) The untreated material has a high density like RNA because the reverse transcript is short and is base-paired to a much longer viral RNA template. (b) The heated material has a density closer to that of DNA because the RNA template has been removed, but it is still denser than pure DNA because of an RNA primer that is covalently attached. (c) The heated and RNase-treated material has the density of a pure DNA because the RNase has removed the RNA primer. The approximate densities of pure RNA and DNA are indicated at top. (Source: Adapted from Verma, I.M., N.L. Menth, E. Bromfeld, K.F. Manly, and D. Baltimore, Covalently linked RNA–DNA molecules as initial product of RNA tumor virus DNA polymerase. Nature New Biology 233:133, 1971.) because each virus particle contains two copies of the RNA genome. After the first jump, the strong-stop DNA is at the right end of the template and can serve as a primer for the reverse transcriptase to copy the rest of the viral RNA (d). PBS LTR gag R U5 pol env LTR U3 R PBS LTR gag U3 R U5 gag U3 R U5 pol pol env env U3 U3 Viral RNA: Provirus LTR R U5 R U5 Figure 23.22 Structures of retroviral RNA and provirus DNA. This is a nondefective retroviral RNA that contains all the genes necessary for replication: a coat protein gene (gag), a reverse transcriptase gene (pol), and an envelope protein gene (env). In addition, it contains long terminal repeats (LTRs) at both ends, but these repeats are not identical. The left LTR contains an R and a U5 region, including a primer-binding site (PBS), shown here bound to a tRNA primer, but the right LTR contains a U3 and an R region. On the other hand, the proviral DNA, made using the viral RNA as a template, contains full LTRs (U3, R, and U5) at each end. wea25324_ch23_732-758.indd Page 749 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile 23.4 Retrotransposons 5′ R U5 PBS 3′ 5′ R U5 PBS 3′ R U5 U3 R 5′ (a) Reverse transcriptase makes strong-stop DNA. 5′ (b) RNase H removes R and U5 RNA. U3 R 3′ U3 R 3′ 5′ PBS 3′ R U5 3′ 5′ (c) First jump. Strong-stop DNA jumps to other end of RNA. 5′ PBS U3 R 3′ 3′ R U5 (d) Reverse transcriptase extends primer. U3 R 3′ U3 R U5 5′ PBS 3′ PBS 5′ 5′ (e) RNase H removes most of viral RNA. 3′ 5′ 3′ PBS U3 R U5 (f) Reverse transcriptase extends RNA primer. 5′ 3′ PBS U3 R U5 PBS U3 U3 R U5 5′ 3′ 5′ (g) RNase H removes viral RNA and tRNA. 3′ PBS 5′ U3 R U5 PBS 3′ U3 R U5 5′ (h) Second jump. PBS sites at opposite ends pair up. 5′ U3 R U5 PBS 3′ 3′ PBS U3 R U5 5′ (i) Both strands filled in by growth at 3′-ends. 5′ U3 R U5 PBS 3′ U3 R U5 PBS 749 strand synthesis (f). After the reverse transcriptase extends this primer to the end, including the PBS region, RNase H removes the remaining RNA (g)—the second strand primer and the tRNA—both of which were paired to DNA. This sets up the second jump (h), in which the PBS region on the right pairs with the one on the left. Like the first jump, the second jump can be visualized as a jump to another molecule, or the other end of the same molecule. If the same molecule is involved in the jump, the DNA can loop around to allow the two PBS regions to base-pair. After the second jump, the stage is set for reverse transcriptase, which can use DNA as a template, or another DNA polymerase to complete both strands (i), using the long single-stranded overhangs at each end as templates. Once the provirus is synthesized, it can be inserted into the host genome by an integrase. This enzyme is originally part of a polyprotein derived from the pol gene, which we have seen also encodes reverse transcriptase and RNase H. The integrase is cut from the polyprotein by a protease, which also starts out as part of the same polyprotein. The protease also cuts itself out of the polyprotein. (It is worth noting that some of the most promising drugs for combatting AIDS are protease inhibitors that target the HIV version of this enzyme.) Once the provirus is integrated into the host genome, it is transcribed by host RNA polymerase II to yield viral RNAs. SUMMARY Retroviruses replicate through an RNA intermediate. When a retrovirus infects a cell, it makes a DNA copy of itself, using a virus-encoded reverse transcriptase to carry out the RNA→DNA reaction, and an RNase H to degrade the RNA parts of RNA–DNA hybrids created during the replication process. A host tRNA serves as the primer for the reverse transcriptase. The finished doublestranded DNA copy of the viral RNA is then inserted into the host genome, where it can be transcribed by host polymerase II. U3 R U5 3′ U3 R U5 5′ Figure 23.23 A model for the synthesis of the provirus DNA from a retroviral RNA template. RNA is in red and DNA is in blue, throughout. The tRNA primer is represented by a cloverleaf with a 39-tag that hybridizes to the primer-binding site (PBS) in the viral RNA. The steps are described more fully in the text. Notice that the first jump has allowed the right LTR to be completed. The U5 and R regions were copied from the left LTR of the viral RNA and the U3 region was copied from the right LTR. In step (e), the RNase H removes most of the viral RNA, but it leaves a small piece of RNA adjacent to the right LTR to serve as a primer for second Retrotransposons All eukaryotic organisms appear to harbor transposons that replicate through an RNA intermediate and therefore depend on reverse transcriptase. These retrotransposons fall into two groups with different modes of replication. The first group includes the retrotransposons with LTRs, which replicate in a manner very similar to retroviruses, except that they do not pass from cell to cell in virus particles. Not surprisingly, these are called LTR-containing retrotransposons. The second group includes the retrotransposons that lack LTRs (the non-LTR retrotransposons). wea25324_ch23_732-758.indd Page 750 750 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile Chapter 23 / Transposition LTR-Containing Retrotransposons The first examples of retrotransposons were discovered in the fruit fly (Drosophila melanogaster) and yeast (Saccharomyces cerevisiae). The prototype Drosophila transposon is called copia because it is present in the genome in copious quantity. In fact, copia and related transposons called copia-like elements account for about 1% of the total fruit fly genome. Similar transposable elements in yeast are called Ty, for “transposon yeast.” These transposons have LTRs that are very similar to the LTRs in retroviruses, which suggests that their transposition resembles the replication of a retrovirus. Indeed, several lines of evidence indicate that this is true. Here is a summary of the evidence that the Ty1 elements replicate through an RNA intermediate, just as retroviruses do: 1. Ty1 encodes a reverse transcriptase. The tyb gene in Ty codes for a protein with an amino acid sequence closely resembling that of the reverse transcriptases encoded in the pol genes of retroviruses. If the Ty1 element really codes for a reverse transcriptase, then this enzyme should appear when Ty1 is induced to transpose; moreover, mutations in tyb should block the appearance of reverse transcriptase. Gerald Fink and his colleagues have performed experiments that bear out both of these predictions. 2. Full-length Ty1 RNA and reverse transcriptase activity are both associated with particles that closely resemble retrovirus particles. These particles appear only in yeast cells that are induced for Ty1 transposition. 3. In a clever experiment, Fink and colleagues inserted an intron into a Ty1 element and then analyzed the element again after transposition. The intron was gone! This finding is incompatible with the kind of transposition bacteria employ, in which the transposed DNA looks just like its parent. But it is consistent with the following mechanism (Figure 23.24): The Ty element is first transcribed, intron and all; then the RNA is spliced to remove the intron; and finally, the spliced RNA is reverse transcribed, perhaps within a virus-like particle, and the resulting DNA is inserted back into the yeast genome at a new location. 4. Jef Boeke and colleagues demonstrated that the host tRNAiMet serves as the primer for Ty1 reverse transcription. First, they mutated 5 of 10 nucleotides in the Ty1 element’s PBS that are complementary to the host tRNAiMet. These changes abolished transposition, presumably because they made it impossible for the tRNA primer to bind to its PBS. Then Boeke and coworkers made five compensating mutations in a copy of the host tRNAiMet gene that restored binding to the mutated PBS. These mutations restored transposition activity to the mutant Ty1 element. As we have seen many times throughout this book, this kind of mutation suppression is powerful evidence for the importance of interaction between two molecules: in this Host DNA Host DNA Ty element: LTR Intron LTR Transcription RNA: Splicing Processed RNA: Reverse transcription (in particle?) Double-stranded DNA: Reinsertion into host DNA Reinserted DNA: Figure 23.24 Model for transposition of Ty. The Ty element has been experimentally supplied with an intron (yellow). The Ty element is transcribed to yield an RNA copy containing the intron. This transcript is spliced, and then the processed RNA is reverse-transcribed, possibly in a virus-like particle. The resulting double-stranded DNA then reinserts into the yeast genome. Abbreviation: LTR 5 long terminal repeat. case, interaction between the tRNAiMet primer and its binding site in the Ty1 element. Copia and its relatives share many of the characteristics we have described for Ty, and it is clear that they also transpose in the same way as Ty. Humans also have LTR-containing retrotransposons, but they lack a functional env gene. The most prominent examples are the human endogenous retroviruses (HERVs), which make up 1–2% of the genome. So far, no transposition-competent HERVs are known, so the HERVs may be relics of previous retrotransposition. SUMMARY Several eukaryotic transposons, includ- ing Ty of yeast and copia of Drosophila, apparently transpose by a mechanism similar to that of retrovirus replication. They start with DNA in the host genome, make an RNA copy, then reverse transcribe it—probably within a virus-like particle—to DNA that can insert in a new location. HERVs probably transposed in the same way until most or all of them lost the ability to transpose. wea25324_ch23_732-758.indd Page 751 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile 751 23.4 Retrotransposons ORF1 5 UTR (a) ORF2 EN RT C 3 UTR 1 0 5 15 30 60 90 120 min An Figure 23.25 Map of the L1 element. The subregions within ORF2 (yellow) are designated EN (endonuclease), RT (reverse transcriptase), and C (cysteine-rich). The purple arrows at each end indicate direct repeats of host DNA, and the An on the right indicates the poly(A). oc Linear sc (b) + RNA Products (%) 100 80 Linear 60 40 Open circle 20 0 (c) 0 20 40 60 80 Time (min) 100 120 – RNA 100 Products (%) Non-LTR Retrotransposons Retrotransposons that lack LTRs are much more abundant than those with LTRs, at least in mammals. The most abundant of all are the long interspersed elements (LINEs), one of which (L1) is present in at least 100,000 copies and makes up about 17% of the human genome, although about 97% of the copies of L1 are missing parts of their 59-ends and the great majority (all but ,60–100 copies) have mutations that prevent their transposition. The prevalence of L1 elements means that this retrotransposon, which has been traditionally classified as “junk DNA,” occupies about five times as much of the genome as all the human exons do. Figure 23.25 is a map of an intact L1 element, showing its two ORFs. ORF1 encodes an RNA-binding protein (p40), and ORF2 encodes a protein with two activities: an endonuclease and a reverse transcriptase. L1, like all retrotransposons in this class, is polyadenylated. We have just seen that the LTR is crucial for replication of most retrotransposons with LTRs, so how do non-LTR retrotransposons replicate? In particular, what do they use for a primer? The answer is that their endonuclease creates a single-stranded break in the target DNA and their reverse transcriptase uses the newly formed DNA 39-end as a primer. Our best information on this mechanism comes from Thomas Eickbush and colleagues’ studies on R2Bm, a LINE-like element from the silkworm Bombyx mori. This element resembles the mammalian LINEs in that it encodes a reverse transcriptase, but no RNase H, protease, or integrase, and it lacks LTRs. But it differs from the LINEs in that it has a specific target site—in the 28S rRNA gene of the host. This latter property made the insertion mechanism easier to investigate. Eickbush and colleagues first showed that the single ORF of R2Bm encodes an endonuclease that specifically cleaves the 28S rDNA target site. Next, they purified the endonuclease (and an RNA cofactor that was required for activity) and added it to a supercoiled plasmid containing the target site. If a single strand of the plasmid is cut, the supercoiled plasmid will be converted to a relaxed circle. If both strands are cut, a linear DNA should appear. Figure 23.26a and b show the rapid appearance of relaxed (open) circles, followed by the slower conversion of open circles to linear DNA. Thus, the R2Bm endonuclease rapidly cleaves one of the DNA strands at the target site, then much more slowly cleaves the other strand. This cleavage is specific: The nuclease cannot cut even one strand of a plasmid that lacks the target site. Open circle 80 60 40 20 0 Linear 0 20 40 60 80 Time (min) 100 120 Figure 23.26 DNA nicking and cleavage activity of the R2Bm endonuclease. Eickbush and colleagues mixed a supercoiled plasmid bearing the target site for the R2Bm retrotransposon with the purified R2Bm endonuclease, with or without its RNA cofactor, then electrophoresed the plasmid to see if it had been nicked (relaxed to an open circular form) or cut in both strands to yield a linear DNA. (a) Electrophoretic gel stained with ethidium bromide. The positions of the supercoiled plasmid (sc), the open circular plasmid (oc), and the linear plasmid (linear) are indicated at right. (b) Graphical representation of the results from panel (a). (c) Results from a similar experiment in which the RNA cofactor was omitted. (Source: Adapted from Luan, D.D., M.H. Korman, J.L. Jakubczak, and T.H. Eickbush, Reverse transcription of R2Bm RNA is primed by a nick at the chromosomal target sige: a mechanism for non-LTR retrotransposition. Cell 72 (Feb 1993) f. 2, p. 597. Reprinted by permission of Elsevier.) wea25324_ch23_732-758.indd Page 752 752 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile Chapter 23 / Transposition Next, these workers removed the RNA cofactor and showed that the protein by itself still caused rapid singlestranded nicking of the target site, but barely detectable cutting of the other strand (Figure 23.26c). They also showed that the linear DNA could be recircularized by T4 DNA ligase, which requires a 59-phosphate group. Thus, cleavage by the R2Bm endonuclease leaves a 59-phosphate and a 39-hydroxyl group. Next, they used the endonuclease to create single-stranded nicks and showed by primer extension analysis that the transcribed strand is the one that is nicked. (The nick in the transcribed strand stopped the DNA polymerase in the primer extension experiment, but primer extension on the other strand proceeded unimpeded by nicks.) With more precise primer extension experiments on DNA cut in both strands, they located the cut sites exactly and found the two strands are cut 2 bp apart. To see if the nicked target DNA strand really does serve as the primer, Eickbush and colleagues performed an in vitro reaction with a short piece of pre-nicked target DNA as primer, R2Bm RNA as template, R2Bm reverse transcriptase, and all four dNTPs, including [32P]dATP. They electrophoresed and autoradiographed the products to see if they were the right size. Figure 23.27a shows what should happen at the molecular level, and panel b shows the results. When a nonspecific RNA was added as template, no product was made (lane 1), but when the R2Bm RNA was added, a strong band at 1.9 kb appeared. Is this what we expect? It is hard to know because we do not know exactly how far the reverse transcriptase traveled and we are dealing with a slightly branched polynucleotide, but it is close because the primer is 1 kb long and the template is 802 nt long. To investigate the nature of the product further, Eickbush and colleagues included dideoxy-CTP in the reaction (lane 3). As expected, it caused premature termination of reverse transcription at a number of sites, leading to a fuzzy band. In another reaction, they treated the product with RNase A to remove any part of the template not basepaired to the reverse transcription product before electrophoresis. Lane 4 shows that this sharpened the product to a 1.8-kb band, suggesting that about 100 nt had been removed from the 59-end of the RNA template, so the reverse transcriptase had apparently not completed its task in the majority of cases. These workers also treated the product with RNase H prior to electrophoresis (lane 5) and obtained a diffuse band of about 1.5 kb. This procedure should remove the RNA template because it is in a hybrid with the product. The fact that the band is still longer than 1 kb indicates that a strand of DNA has been extended. Lane 6 is another negative control in which a nonspecific DNA was used instead of the target DNA. Similar experiments with a target DNA that extended farther to the left (with the target site in the middle) showed a predominance of large, Y-shaped products (as predicted in Figure 23.27), suggesting that reverse transcription occurred before second-strand cleavage. If second-strand (a) 1000 bp 802 nt 3′ 5′ 3′ 5′ 1 (b) 2 3 4 5 6 2.7 1.9 1.0 Figure 23.27 Evidence for target priming of reverse transcription of R2Bm. (a) Model of the product we expect if the R2Bm endonuclease makes a nick near the left end of a 1-kb target DNA and uses the new 39-end to prime reverse transcription of an 802-nt transposon RNA. The reverse transcript (blue) is covalently attached to the primer (yellow). The rest of the lower DNA strand is also rendered in yellow at left. The opposite DNA strand is black. (b) Experimental results. Eickbush and colleagues started with a 1-kb target DNA with the target site close to the left end. They added R2Bm RNA and the ORF2 product and dNTPs, including [32P]dATP to allow labeled reverse transcripts to be formed. Then they electrophoresed the products and autoradiographed them. Lane 1, a nonspecific RNA was used instead of R2Bm RNA; lanes 2–6, R2Bm RNA was used; lane 3, dideoxy-CTP was included in the reverse transcription reaction; lane 4, the product was treated with RNase A before electrophoresis; lane 5, the product was treated with RNase H before electrophoresis; lane 6, a nonspecific target DNA was used. (Source: Luan, D.D., M.H. Korman, J.L. Jakubczak, and T.H. Eickbush, Reverse transcription of R2Bm RNA is primed by a nick at the chromosomal target site: a mechanism for non-LTR retrotransposition Cell 72 (Feb 1993) f. 4, p. 599. Reprinted by permission of Elsevier Science.) cleavage had occurred first, the products would have been linear and smaller. To confirm that the target DNA was serving as the primer, Eickbush and coworkers performed PCR with primers that hybridized to the target DNA and to the reverse transcript, and obtained PCR products of the expected size and sequence. Based on these and other data, H.H. Kazazian and John Moran proposed the model of L1 transposition presented in Figure 23.28. First, the transposon is transcribed and the transcript is processed. The processed mRNA leaves the nucleus to be translated in the cytoplasm. It associates with its two products, p40 and the ORF2 product, and reenters the nucleus. There, the endonuclease activity of the ORF2 product nicks the target DNA. For L1, the target can be wea25324_ch23_732-758.indd Page 753 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile 23.4 Retrotransposons L1 element ORF1 ORF2 (a) Transcription, processing, and export AAAn mRNA (b) Translation and RNP assembly p40 p40 ORF2 AAAn RNP ORF2 O RF 2 OR F2 AA TT An T n (c) Import into nucleus and target primed reverse transcription (d) Second-strand synthesis and full integration at new site Figure 23.28 A model for L1 transposition. (a) The L1 element is transcribed, processed, and exported from the nucleus. (b) The mRNA is translated to yield the ORF1 product (p40), and the ORF2 product, with endonuclease and reverse transcriptase activities. These proteins associate with the mRNA to form an RNP (c) The ribonucleoprotein reenters the nucleus. The endonuclease nicks the target DNA (anywhere in the genome), and the reverse transcriptase uses the new DNA 39-end to prime synthesis of the reverse transcript. (d) In a series of unspecified steps, the second L1 strand is made and the element, usually truncated at its 59-end, is ligated into the target DNA. any region of the DNA. Then the reverse transcriptase activity of the ORF2 product uses the target DNA 39-end created by the endonuclease as a primer to copy the L1 RNA. Thus, this mechanism is called target-primed retrotransposition. Finally, in steps that are still poorly understood, the second strand of L1 is made, the second strand 753 of the target is cleaved, and the L1 element is ligated into its new home. At the beginning of this section, we learned that L1 elements comprise about 17% of the human genome. And, as we will soon see, these elements can carry pieces of genomic DNA with them as they transpose. Thus, one can estimate that, directly or indirectly, L1 elements have sculpted about 30% of the human genome. Furthermore, L1-like elements have been found in both plants and animals. Thus, these elements are ancient—at least 600 million years old. And, because identical DNA sequences can lose all resemblance to each other after about 200 million years of evolution, the true contribution of L1 elements to the human genome may actually be about 50%. You would suspect that anything as prevalent as L1 is in the human genome must have some negative consequences, and indeed a number of L1-mediated mutations have been discovered that have led to human disease. In particular, copies of L1 have been found: in the blood clotting factor VIII gene, causing hemophilia; in the DMD gene, causing Duchenne muscular dystrophy; and in the APC gene, helping to cause adenomatous polyposis coli, a kind of colon cancer. In this last case, the patient’s cancer cells had the L1 element in their APC gene, but the normal cells did not. Thus, this transposition had occurred during the patient’s lifetime as a somatic mutation. What is more surprising is that the L1 elements may actually have beneficial consequences as well. For example, significant homology occurs between the reverse transcriptase of L1 and human telomerase, suggesting that L1 may have been the origin of the enzyme that maintains the ends of our chromosomes (although the reverse may also have been true). But the most plausible beneficial aspect of L1 is that it may facilitate exon shuffling, the exchange of exons among genes. This happens because the polyadenylation signal of L1 is weak, so the polyadenylation machinery frequently bypasses it in favor of a polyadenylation site downstream in the host part of the transcript. RNAs polyadenylated in that way will include a piece of human RNA attached to the L1 RNA, and this human RNA will be incorporated as a reverse transcript wherever the L1 element goes next. This is bound to have deleterious consequences sometimes, but it also creates new genes out of parts of old genes, and that can give rise to proteins with new and useful characteristics. Why are the polyadenylation signals of L1 elements weak? Moran offers the following explanation: If the polyadenylation signals were strong, insertion of these elements into the introns of human genes would cause premature polyadenylation of transcripts, so all the exons downstream would be lost. That would probably inactivate the gene and might well lead to the death of the host. And, unlike retroviruses, which can move from one individual to another, the L1 elements live and die with their hosts. On the other hand, weak polyadenylation signals allow these wea25324_ch23_732-758.indd Page 754 754 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile Chapter 23 / Transposition elements to insert into introns of human genes without disrupting a very high percentage of the transcripts of these genes. Thus, because the amount of DNA devoted to introns is much higher than that devoted to exons, the L1 elements have a large area of the human genome to colonize relatively safely. SUMMARY LINEs and LINE-like elements are ret- rotransposons that lack LTRs. These elements encode an endonuclease that nicks the target DNA. Then the element takes advantage of the new DNA 39-end to prime reverse transcription of element RNA. After second-strand synthesis, the element has become replicated at its target site. A new round of transposition begins when the LINE is transcribed. Because the LINE polyadenylation signal is weak, transcription of a LINE can include one or more downstream exons of host DNA. Nonautonomous Retrotransposons Members of another class of non-LTR retrotransposons (nonautonomous retrotransposons) encode no proteins, so they are not autonomous like the transposition-competent LINEs. Instead, they depend on other elements, probably the LINEs due to their prevalence, to supply the proteins, including the reverse transcriptase they need to transpose. The best studied of these nonautonomous retrotransposons are the Alu elements, so-called because they contain the sequence AGCT that is recognized by the restriction enzyme AluI. These are about 300 bp long and are present in up to a million copies in the human genome. Thus, they have been even more successful than the LINEs. One reason for this success may be that the transcripts of the Alu elements contain a domain that resembles the 7SL RNA that is normally part of the signal recognition particle that helps attach certain ribosomes to the endoplasmic reticulum. Two signal recognition particle proteins bind tightly to Alu element RNA and may carry it to the ribosomes, where the LINE RNA is being translated. This may put the Alu element RNA in a position to help itself to the proteins it needs to be reverse transcribed and inserted at a new site. Because of their small size, Alu elements and similar elements are called short interspersed elements (SINEs). The LINEs have probably also played a role in shaping the human genome by facilitating the creation of processed pseudogenes. Ordinary pseudogenes are DNA sequences that resemble normal genes, but for one reason or another cannot function. Sometimes they have internal translation stop signals; sometimes they have inactive or missing splicing signals; sometimes they have inactive promoters; usually a combination of problems prevents their expression. They apparently arise by gene duplication and subsequently accumulate mutations. This process has no delete- rious effect on the host because the original gene remains functional. Processed pseudogenes also arise by gene duplication, but apparently by way of reverse transcription. We strongly suspect that RNA is an intermediate in the formation of processed pseudogenes because: (1) these pseudogenes frequently have short poly(dA) tails that seem to have derived from poly(A) tails on mRNAs; and (2) processed pseudogenes lack the introns that their progenitor genes usually have. As in the case of the Alu elements, which are not derived from mRNAs, the LINEs could provide the molecular machinery that allows mRNAs to be reverse transcribed and inserted into the host genome. SUMMARY Nonautonomous retrotransposons in- clude the very abundant Alu elements in humans and similar elements in other vertebrates. They cannot transpose by themselves because they do not encode any proteins. Instead they take advantage of the retrotransposition machinery of other elements, such as LINEs. Processed pseudogenes probably arose in the same way: mRNAs were reversetranscribed by LINE machinery and then inserted into the genome. Group II introns In Chapter 14 we learned that group II introns, which inhabit bacterial, mitochondrial, and chloroplast genomes, are self-splicing introns that form a lariat intermediate. In 1998, Marlene Belfort and colleagues discovered that a group II intron in a particular gene could insert into an intronless version of the same gene somewhere else in the genome. This process, called retrohoming, appears to occur by the mechanism outlined in Figure 23.29. The gene bearing the intron is first transcribed, then the intron is spliced out as a lariat. This intron can then recognize an intronless version of the same gene and invade it by reverse-splicing. Reverse transcription creates a cDNA copy of the intron, and second-strand synthesis replaces the RNA intron with a second strand of DNA. In 1991, Phillip Sharp proposed that group II introns could be the ancestors of modern spliceosomal introns, in part because of their very similar mechanisms of splicing. In 2002, Belfort and colleagues showed how this could have happened. They detected true retrotransposition, not just retrohoming, of a bacterial group II intron. Thus, the intron moved to a variety of new sites, not just to an intronless copy of the intron’s home gene. To detect retrotransposition, Belfort and colleagues built a plasmid with a modified version of the group II Lactococcus lactis L1. LtrB intron, containing a kanamycin resistance gene in reverse orientation, interrupted by a selfsplicing group I intron. In order for kanamycin resistance to be expressed, this group II intron would first have to be wea25324_ch23_732-758.indd Page 755 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile Summary Intron Donor gene X (a) Transcription (b) Splicing Lariat intron Intronless gene X (same, or similar, sequence as donor) (c) Reverse splicing (d) Reverse transcription (e) Second-strand synthesis Figure 23.29 Retrohoming. (a) The donor gene X (blue) bearing a group II intron (red) is transcribed to yield an RNA (RNAs are shaded throughout). (b) The transcript is spliced, yielding a lariat-shaped intron. (c) The intron reverse-splices itself into another copy of gene X that has the same or similar sequence as the first except that it lacks the intron. (d) The intron-encoded reverse transcriptase makes a DNA copy of the intron, using a nick in the bottom DNA strand as primer. The arrowhead marks the 39-end of the growing reverse transcript. (e) The second strand (DNA version) of the intron is made, replacing the RNA intron in the top strand. This completes the retrohoming process. transcribed, so the interrupting group I intron could be removed. Then, the transcript would have to be reversetranscribed to yield a DNA that could insert into the host DNA, where it could be transcribed in the forward, rather than the reverse direction. As long as the group II intron remained in RNA form, it could not code for kanamycin resistance because its resistance gene had been transcribed in the reverse direction, yielding an antisense RNA. 755 When Belfort and colleagues selected for kanamycinresistant cells, they found that transposition was relatively rare, but did occur at a measurable rate. An interesting feature of this transposition was that most of it occurred into the DNA replication lagging strand. This finding suggested that transposition happened during replication and used the short DNA fragments created in the lagging strand (Chapter 20) as primers for the kind of target-primed reverse transcription we saw in the L1 transposition scheme in Figure 23.28. Notice that no homology between the transposon and the target DNA is required for this mechanism, as nicks in replicating lagging strands occur everywhere in the genome. Once a group II intron has retrotransposed, it retains its ability to splice itself out, so the target gene should usually continue to function. Thus, the proliferation of group II introns may have occurred readily and with relative safety in the precursors to modern eukaryotes. Ultimately, eukaryotes appear to have developed spliceosomes to make the splicing process more efficient. SUMMARY Group II introns can retrohome to in- tronless copies of the same gene by insertion of an RNA intron into the gene, followed by reverse transcription and second-strand synthesis. Group II introns can also undergo retrotransposition by insertion of an RNA intron into an unrelated gene by target-primed reverse transcription, using lagging strand DNA fragments as primers. This kind of retrotransposition of group II introns may have provided the ancestors of modern-day eukaryotic spliceosomal introns and may account for their widespread appearance in higher eukaryotes. S U M M A RY Transposable elements, or transposons, are pieces of DNA that can move from one site to another. Some transposable elements replicate, leaving one copy at the original location and placing one copy at a new site; others transpose without replication, leaving the original location altogether. Bacterial transposons include the following types: (1) insertion sequences such as IS1 that contain only the genes necessary for transposition, flanked by inverted terminal repeats; (2) transposons such as Tn3 that are like insertion sequences but contain at least one extra gene, usually a gene that confers antibiotic resistance. Eukaryotic transposons use a wide variety of replication strategies. The DNA transposons, such as Ds and Ac of maize and the P elements of Drosophila behave like the DNA transposons, such as Tn3, of bacteria. wea25324_ch23_732-758.indd Page 756 756 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile Chapter 23 / Transposition The immunoglobulin genes of mammals rearrange using a mechanism that resembles transposition. Vertebrate immune systems create enormous diversity in the kinds of immunoglobulins they can make. The primary source of this diversity is the assembly of genes from two or three component parts, each selected from a heterogeneous pool of parts. This assembly of gene segments is known as V(D)J recombination. The recombination signal sequences (RSSs) in V(D)J recombination consist of a heptamer and a nonamer separated by either 12-bp or 23-bp spacers. Recombination occurs only between a 12 signal and a 23 signal, which ensures that only one of each kind of coding region is incorporated into the rearranged gene. RAG1 and RAG2 are the principal players in human V(D)J recombination. They introduce single-strand nicks into DNA adjacent to either a 12 signal or a 23 signal. This leads to a transesterification in which the newly created 39-hydroxyl group attacks the opposite strand, breaking it, and forming a hairpin at the end of the coding segment. The hairpins then break and join with each other in an imprecise way, allowing joining of coding regions with loss of bases or gain of extra bases. The retrotransposons come in two different types. The LTR-containing retrotransposons replicate like retroviruses, which replicate through an RNA intermediate as follows: When a retrovirus infects a cell, it makes a DNA copy of itself, using a virus-encoded reverse transcriptase to carry out the RNA→DNA reaction, and an RNase H to degrade the RNA parts of RNA–DNA hybrids created during the replication process. A host tRNA serves as the primer for the reverse transcriptase. The finished double-stranded DNA copy of the viral RNA is then inserted into the host genome, where it can be transcribed by host polymerase II. The retrotransposons Ty of yeast and copia of Drosophila replicate in much the same way. They start with DNA in the host genome, make an RNA copy, then reversetranscribe it—probably within a virus-like particle—to DNA that can insert in a new location. The other class of eukaryotic retrotransposons are the non-LTR retrotransposons, and they use different methods of priming reverse transcription. For example, LINEs and LINE-like elements encode an endonuclease that nicks the target DNA. Then the element takes advantage of the new DNA 39-end to prime reverse transcription of element RNA. After second-strand synthesis, the element has become replicated at its target site. A new round of transposition begins when the LINE is transcribed. Because the LINE polyadenylation signal is weak, transcription of a LINE frequently includes one or more downstream exons of host DNA and this can transport host exons to new locations in the genome. Nonautonomous, non-LTR retrotransposons include the very abundant Alu elements in humans and similar elements in other vertebrates. They cannot transpose by themselves because they do not encode any proteins. Instead, they take advantage of the retrotransposition machinery of other elements, such as LINEs. Processed pseudogenes probably arose in the same way: mRNAs were probably reverse-transcribed by LINE machinery and then inserted into the genome. Group II introns represent another class of non-LTR retrotransposons found in both bacteria and eukaryotes. They can retrohome to intronless copies of the same gene by insertion of an RNA intron into the gene, followed by reverse transcription and second-strand synthesis. Group II introns can also undergo retrotransposition by insertion of an RNA intron into an unrelated gene by target-primed reverse transcription, perhaps using lagging strand DNA fragments as primers. This kind of retrotransposition of group II introns may have provided the ancestors of modernday eukaryotic spliceosomal introns and may account for their widespread appearance in higher eukaryotes. REVIEW QUESTIONS 1. Describe and give the results of an experiment that shows that bacterial transposons contain inverted terminal repeats. 2. Compare and contrast the genetic maps of the bacterial transposons IS1 and Tn3, and the eukaryotic transposon Ac. 3. Diagram the mechanism of Tn3 transposition, first in simplified form, then in detail. 4. Diagram a mechanism for nonreplicative transposition. 5. Explain how transposition can give rise to speckled maize kernels. 6. Draw a sketch of an antibody protein, showing the light and heavy chains. 7. Explain how thousands of immunoglobulin genes can give rise to many millions of antibody proteins. 8. Diagram the rearrangement of immunoglobulin lightand heavy-chain genes that occurs during B-lymphocyte maturation. 9. Explain how the signals for V(D)J joining ensure that one and only one of each of the parts of an immunoglobulin gene will be included in the mature, rearranged gene. 10. Diagram a reporter plasmid designed to test the importance of the heptamer, nonamer, and spacer in a recombination signal sequence. Explain how this plasmid detects recombination. 11. Present a model for cleavage and rejoining of DNA strands at immunoglobulin gene recombination signal sequences. How does this mechanism contribute to antibody diversity? 12. Describe and give the results of an experiment that shows that cleavage at an immunoglobulin recombination signal sequence leads to formation of a hairpin in vitro. 13. Present evidence for a reverse transcriptase activity in retrovirus particles and the effects of RNase on this activity. wea25324_ch23_732-758.indd Page 757 12/21/10 1:53 PM user-f469 /Volume/204/MHDQ268/wea25324_disk1of1/0073525324/wea25324_pagefile Suggested Readings 14. Describe and show the results of an experiment that demonstrates that strong-stop reverse transcripts in retroviruses are base-paired to the RNA genome and covalently attached to an RNA primer. 15. Illustrate the difference between the structures of the LTRs in genomic retroviral RNAs and retroviral proviruses. 16. Diagram the conversion of a retrovirus RNA to a provirus. Show how this explains the difference in the previous question. 17. Compare and contrast the mechanisms of retrovirus replication and retrotransposon transposition. 18. Summarize the evidence that retrotransposons transpose via an RNA intermediate. 19. Describe and show the results of an experiment that demonstrates that the endonuclease of a LINE-like element can specifically nick one strand of the element’s target DNA. 20. Describe and show the results of an experiment that demonstrates that a LINE-like element can use a nicked strand of its target DNA as a primer for reverse transcription of the element. 21. Present a model for retrotransposition of a LINE-like element. c. d. 757 Inhibitors of reverse transcription Inhibitors of translation 7. You have identified a new transposon you call Rover. You want to determine whether Rover transposes by a retrotransposon mechanism or by a standard replication transposition mechanism such as that used by Tn3. Describe an experiment you would use to answer this question, and tell what the results would be in each case. 8. You are a molecular biologist interested in learning more about the fascinating process of V(D)J recombination. Assuming that you are capable of generating all of the following possible variants, explain what effect (from a molecular process standpoint as well as a physiological and/or immunological standpoint) you would expect to observe if the following were created in your laboratory: a. the removal of all of the D gene segments from the section of the genome encoding the heavy chain of antibodies. b. the removal of all of the D gene segments from the section of the genome encoding the beta chain of T-cell receptors. c. the genetic alteration of the RSS flanking the D gene segments from a 12 signal to a 23 signal. d. the elimination of expression of the RAG gene products. A N A LY T I C A L Q U E S T I O N S 1. A certain transposon’s transposase creates staggered cuts in the host DNA five base pairs apart. What consequence does this have for the host DNA surrounding the inserted transposon? Draw a diagram to explain how the staggered cuts affect the host DNA. 2. You are interested in measuring the rate of transfer of a hypothetical transposon, Stealth, from one plasmid, carrying two antibiotic resistance genes of its own, to another plasmid, which carries the gene for chloramphenicol resistance. (Stealth carries an ampicillin resistance gene.) Describe an experiment you would perform to assay for this transposition. 3. Identify the end product of abortive transposition carried out by Tn3 transposons with mutations in the following genes. a. Transposase b. Resolvase 4. Transposon TnT in plasmid A transposes to plasmid B. How many copies of TnT are in the cointegrate? Where are they with respect to the two plasmids in the cointegrate? 5. If the transposable element Ds of maize transposed by the same mechanism as Tn3, would we see the speckled kernels with the same high frequency? Why, or why not? 6. Assume you have two cell-free transposition systems that have all the enzymes necessary for transposition of Tn3 and Ty, respectively. What effect would the following inhibitors have on these two systems, and why? a. Inhibitors of double-stranded DNA replication b. Inhibitors of transcription SUGGESTED READINGS General References and Reviews Baltimore, D. 1985. Retroviruses and retrotransposons: The role of reverse transcription in shaping the eukaryotic genome. Cell 40:481–82. Cohen, S.N. and J.A. Shapiro. 1980. Transposable genetic elements. Scientific American 242 (February):40–49. Craig, N.L. 1996 V(D)J recombination and transposition: Closer than expected. Science 271:1512. Doerling, H.-P. and P. Starlinger. 1984. Barbara McClintock’s controlling elements: Now at the DNA level. Cell 39:253–59. Eickbush, T.H. 2000. Introns gain ground. Nature 404:940–41. Engels, W.R. 1983. The P family of transposable elements in Drosophila. Annual Review of Genetics 17:315–44. Federoff, N.V. 1984. Transposable genetic elements in maize. Scientific American 250(June):84–99. Grindley, N.G.F. and A.E. Leschziner. 1995. 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